Thursday, November 21, 2013

Aerocarnival

4)It took MegaTech, Inc. 100,000 labor-hours to prepare the head start of several oil bore rigs for wintry exploration. Your company, Natural Resources, Inc. has agreed to purchase the fifth oil cut rig from their manufacturing yard. Assume that MegaTech experiences a learning crop of 80%. At a labor rate of $35 per hour, what should you, as the purchasing agent expect to pay for the fifth unscathed? Remember, the simplified formula for calculating learning rate poster is given as: TN = T1C Where, TN = Time needed to produce the n-th unit T1= Time needed to produce the first unit C= acquirement curved shape coefficient Answer The control panel lists the fourth unit learning curve coefficient as .596, assuming a learning rate of 80%. Using the formula, to produce the fifth unit takes: T5 = (100,000) (.596) = 59,600 hours To find the personify, calculate the hours by the hourly rate: = (59,600) ($35 per hour) = $2,086,000 6)Supp ose that you ar the assigning costs to a major enter to be undertaken by your firm, DynoSoft Applications, this year. One occurrence code process involves some(prenominal) labor hours, but highly senseless work. You anticipate a total of 200,000 labor hours to complete the first grummet of the coding and a learning curve rate of 70%.
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You be attempting to estimate the cost of the twentieth looping of this coding sequence. establish on the above information and at a $60 per hour labor rate, what would you expect to work out as the cost of the twentieth loop? The fortieth iteration? Answer T20=T1C =(200,000) (.214) =42,800 hours T40=! T1C =(200,000) (.150) =30,000 hours The costs for the twentieth and 40th iterations atomic human activity 18 found as: 20th iteration: (42,800 hours) ($60 per hour) =$2,568,000 40th iteration: (30,000 hours) ($60 per hour) =$1,800,000 7)Assume you are a project cost engineer calculating the cost of a insistent activity for your project. There are a total of 20...If you exigency to get a full essay, straddle it on our website: BestEssayCheap.com

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